3.1624 \(\int \frac {1}{(a+\frac {b}{x})^2} \, dx\)

Optimal. Leaf size=34 \[ -\frac {2 b \log (a x+b)}{a^3}+\frac {2 x}{a^2}-\frac {x}{a \left (a+\frac {b}{x}\right )} \]

[Out]

2*x/a^2-x/a/(a+b/x)-2*b*ln(a*x+b)/a^3

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Rubi [A]  time = 0.01, antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {192, 193, 43} \[ -\frac {2 b \log (a x+b)}{a^3}+\frac {2 x}{a^2}-\frac {x}{a \left (a+\frac {b}{x}\right )} \]

Antiderivative was successfully verified.

[In]

Int[(a + b/x)^(-2),x]

[Out]

(2*x)/a^2 - x/(a*(a + b/x)) - (2*b*Log[b + a*x])/a^3

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 192

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Simp[(x*(a + b*x^n)^(p + 1))/(a*n*(p + 1)), x] + Dist[(n*(p +
1) + 1)/(a*n*(p + 1)), Int[(a + b*x^n)^(p + 1), x], x] /; FreeQ[{a, b, n, p}, x] && ILtQ[Simplify[1/n + p + 1
], 0] && NeQ[p, -1]

Rule 193

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Int[x^(n*p)*(b + a/x^n)^p, x] /; FreeQ[{a, b}, x] && LtQ[n, 0]
&& IntegerQ[p]

Rubi steps

\begin {align*} \int \frac {1}{\left (a+\frac {b}{x}\right )^2} \, dx &=-\frac {x}{a \left (a+\frac {b}{x}\right )}+\frac {2 \int \frac {1}{a+\frac {b}{x}} \, dx}{a}\\ &=-\frac {x}{a \left (a+\frac {b}{x}\right )}+\frac {2 \int \frac {x}{b+a x} \, dx}{a}\\ &=-\frac {x}{a \left (a+\frac {b}{x}\right )}+\frac {2 \int \left (\frac {1}{a}-\frac {b}{a (b+a x)}\right ) \, dx}{a}\\ &=\frac {2 x}{a^2}-\frac {x}{a \left (a+\frac {b}{x}\right )}-\frac {2 b \log (b+a x)}{a^3}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 29, normalized size = 0.85 \[ \frac {-\frac {b^2}{a x+b}-2 b \log (a x+b)+a x}{a^3} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b/x)^(-2),x]

[Out]

(a*x - b^2/(b + a*x) - 2*b*Log[b + a*x])/a^3

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fricas [A]  time = 1.07, size = 47, normalized size = 1.38 \[ \frac {a^{2} x^{2} + a b x - b^{2} - 2 \, {\left (a b x + b^{2}\right )} \log \left (a x + b\right )}{a^{4} x + a^{3} b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b/x)^2,x, algorithm="fricas")

[Out]

(a^2*x^2 + a*b*x - b^2 - 2*(a*b*x + b^2)*log(a*x + b))/(a^4*x + a^3*b)

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giac [A]  time = 0.15, size = 34, normalized size = 1.00 \[ \frac {x}{a^{2}} - \frac {2 \, b \log \left ({\left | a x + b \right |}\right )}{a^{3}} - \frac {b^{2}}{{\left (a x + b\right )} a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b/x)^2,x, algorithm="giac")

[Out]

x/a^2 - 2*b*log(abs(a*x + b))/a^3 - b^2/((a*x + b)*a^3)

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maple [A]  time = 0.00, size = 34, normalized size = 1.00 \[ \frac {x}{a^{2}}-\frac {b^{2}}{\left (a x +b \right ) a^{3}}-\frac {2 b \ln \left (a x +b \right )}{a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(a+b/x)^2,x)

[Out]

x/a^2-2*b*ln(a*x+b)/a^3-1/a^3*b^2/(a*x+b)

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maxima [A]  time = 1.25, size = 36, normalized size = 1.06 \[ -\frac {b^{2}}{a^{4} x + a^{3} b} + \frac {x}{a^{2}} - \frac {2 \, b \log \left (a x + b\right )}{a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b/x)^2,x, algorithm="maxima")

[Out]

-b^2/(a^4*x + a^3*b) + x/a^2 - 2*b*log(a*x + b)/a^3

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mupad [B]  time = 1.06, size = 36, normalized size = 1.06 \[ \frac {x}{a^2}-\frac {b^2}{x\,a^4+b\,a^3}-\frac {2\,b\,\ln \left (b+a\,x\right )}{a^3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(a + b/x)^2,x)

[Out]

x/a^2 - b^2/(a^3*b + a^4*x) - (2*b*log(b + a*x))/a^3

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sympy [A]  time = 0.17, size = 31, normalized size = 0.91 \[ - \frac {b^{2}}{a^{4} x + a^{3} b} + \frac {x}{a^{2}} - \frac {2 b \log {\left (a x + b \right )}}{a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b/x)**2,x)

[Out]

-b**2/(a**4*x + a**3*b) + x/a**2 - 2*b*log(a*x + b)/a**3

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